In most
Geometry classes, students are taught five different ways to prove two
triangles congruent: SSS, SAS, ASA, AAS, and HL. Each “S” stands for “side”, and each “A”
stands for “angle”, so SSS means that two triangles can be proven congruent if
all three sides are congruent, SAS means that two triangles can be proven
congruent if two sides and the included angle are congruent, ASA means that two
triangles can be proven congruent if two angles and the included side are
congruent, and AAS means that two triangles can be proven congruent if two
angles and the non-included side are congruent.
The last congruence, HL, stands for “hypotenuse-leg”, which means that
two right angle triangles can be proven congruent if one leg and the hypotenuse
are congruent.
Students are
also taught that SSA (or ASS) is not a way to prove triangles congruent,
because in some cases two different triangles can be formed by two given sides
and a non-included angle. With a picture
of this counter-example and a predictable lame joke about how we should have no
postulates named after a donkey, the teacher (or text) closes the discussion
on the matter.
However, SSA is a legitimate congruence
theorem if the given angle is not an acute angle. This is already evident for right angle triangles,
because the HL congruence theorem is really an SSA congruence theorem in
disguise. But it is also true when the given
angle is obtuse as well. In the typical
counter-example for SSA, the law of sines and the identity sin(x) = sin(180° –
x) can be used to prove that the two different (non-right) triangles have a
second angle that is always acute in one case and always obtuse in the other
case:
01
|
by the law of sines, sin B = b/a
sin A
|
02
|
by a trigonometric identity, sin x = sin (180° – x)
|
03
|
therefore, two possible solutions for ∠B are x and 180° – x
|
04
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in a non-right triangle, x is either acute or obtuse
|
05
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if x is acute, then 180° – x is obtuse
|
06
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if x is obtuse, then 180° – x is acute
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07
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either way, one solution for ∠B is acute and one solution for ∠B is obtuse
|
However, if
the given first angle is already obtuse, then there cannot be a second obtuse
angle because the angle sum of the triangle would be more than 180°. This leaves only one possible way to form the
triangle, which means SSA is a legitimate congruence theorem when the given angle
is obtuse.
(if the given angle is obtuse)
Thanks. I had noticed that SSA serves as proof when an obtuse angle is given. I wondered why it is not in the standaard books.
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DeleteThanks david, finaly i've got fascinating explanation, but im stil wondering, why only rhs postulate, for obtuse triangle doesnt mention as postulate too?
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