At some
point in high school, most students learn how to factor a difference of
cubes. The general formula for factoring
a difference of cubes is x3 – y3 = (x – y)(x2
+ xy + y2). So to factor a3
– 64, we would let x = a and y = 4, which means a3 – 64 = a3
– 43 = (a – 4)(a2 + a∙4 + 42) = (a – 4)(a2
+ 4a + 16).
Many
students erroneously try to factor the x2 + xy + y2 part,
but it can’t be done with real numbers. Other quadratics can be factored, such
as x2 + 10x + 16. (To factor
x2 + 10x + 16, we would need to numbers p and q that multiply to 16
and add up to 10. These two numbers are
p = 2 and q = 8, so x2 + 10x + 16 = (x + 2)(x + 8).) But to factor x2 + xy + y2,
we would need two numbers to multiply to y2 and one number to add up
to y. In other words, two numbers p and
q such that pq = y2 and p + q = y.
This means that q = y – p, and p(y – p) = y2 or py – p2
= y2 or p2 – py + y2 = 0. The discriminant of this quadratic equation
is b2 – 4ac = (-y)2 – 4∙1∙y2 = -3y2
which is always negative, which means there are always two imaginary answers
and zero real answers, which makes x2 + xy + y2 not
factorable with integers.
But even
though it can’t be factored, x2 + xy + y2 has some
amazing properties. When x = 1 and y =
1, which we will denote as (1, 1), 12 + 1∙1 + 12 =
3. Continuing in this fashion, (1, 2) =
7, (1, 3) = 13, (1, 4) = 21, and (1, 5) = 31, etc. Let’s investigate x2
+ xy + y2 by making a number chart.
1
|
2
|
3
|
4
|
5
|
6
|
7
|
8
|
9
|
10
|
|
1
|
3
|
7
|
13
|
21
|
31
|
43
|
57
|
73
|
91
|
111
|
2
|
7
|
12
|
19
|
28
|
39
|
52
|
67
|
84
|
103
|
124
|
3
|
13
|
19
|
27
|
37
|
49
|
63
|
79
|
97
|
117
|
139
|
4
|
21
|
28
|
37
|
48
|
61
|
76
|
93
|
112
|
133
|
156
|
5
|
31
|
39
|
49
|
61
|
75
|
91
|
109
|
129
|
151
|
175
|
6
|
43
|
52
|
63
|
76
|
91
|
108
|
127
|
148
|
171
|
196
|
7
|
57
|
67
|
79
|
93
|
109
|
127
|
147
|
169
|
193
|
219
|
8
|
73
|
84
|
97
|
112
|
129
|
148
|
169
|
192
|
217
|
244
|
9
|
91
|
103
|
117
|
133
|
151
|
171
|
193
|
217
|
243
|
271
|
10
|
111
|
124
|
139
|
156
|
175
|
196
|
219
|
244
|
271
|
300
|
Now that we
have a made a table of values, we can make several interesting observations
about x2 + xy + y2.
Here are ten of those observations.
1)
x2
+ xy + y2 has the commutative property, but not the associative or
distributive properties.
The function
x2 + xy + y2 is commutative, because (x, y) = x2
+ xy + y2 = y2 + yx + x2 = (y, x). However, x2 + xy + y2
is not associative or distributive. We
can show that it is not associative by giving a counter-example of ((2, 3), 4)
≠ (2, (3, 4)), because ((2, 3), 4) = (19, 4) = 453 but (2, (3, 4)) = (2, 37) =
1447. We can also show that it is not
distributive by giving a counter-example of (2, (3 + 4)) ≠ (2, 3) + (2, 4),
because (2, (3 + 4)) = (2, 7) = 67 but (2, 3) + (2, 4) = 19 + 28 = 47. The expression x2 + xy + y2
also has an identity but it is not apparent from the table of values since it
is usually an imaginary number. If there
is an identity e so that (x, e) = x, then x2 + xe + e2 =
x, or e2 + xe + x2 – x = 0. Using the quadratic equation, e = ½(-x ±
Ö(x2 – 4(x2
– x))) = -½x ± ½Ö(-3x2 +
4x). This means that the identity for 2
is -½(2) ± ½Ö(-3(2)2 + 4(2))
= -1 ± i.
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